Matematika

Pertanyaan

diketahui AB = 9 cm, BC = 12cm, AE = 20 cm. keliling segitiga ACG adalah..... pakai cara yaa :)
diketahui AB = 9 cm, BC = 12cm, AE = 20 cm. keliling segitiga ACG adalah..... pakai cara yaa :)

2 Jawaban

  • AB = 9 cm
    BC = 12 cm
    AE = CG = 20 cm

    AC = √(AB² + BC²)
    AC = √(9² + 12²)
    AC = √(81 + 144)
    AC = √225
    AC = 15 cm

    AG = √(AC² + CG²)
    AG = √(15² + 20²)
    AG = √(225 + 400)
    AG = √625
    AG = 25 cm

    Keliling segitiga ACG
    = AC + CG + AG
    = 15 + 20 + 25
    = 35 + 25
    = 60 cm (Opsi A)
  • Keliling ACG = AC+CG+AG
    AC² = AB² + BC²
    = 9² + 12²
    = 225
    AC = √225 = 15 cm
    CG = AE = 20 cm
    AG² = AC² + CG²
    = 15² + 20²
    = 625
    AG = √625 = 25 cm
    K = AC+CG+AG
    = 15+20+25
    = 60 cm (a)