diketahui AB = 9 cm, BC = 12cm, AE = 20 cm. keliling segitiga ACG adalah..... pakai cara yaa :)
Matematika
jasminecintai
Pertanyaan
diketahui AB = 9 cm, BC = 12cm, AE = 20 cm. keliling segitiga ACG adalah..... pakai cara yaa :)
2 Jawaban
-
1. Jawaban Anonyme
AB = 9 cm
BC = 12 cm
AE = CG = 20 cm
AC = √(AB² + BC²)
AC = √(9² + 12²)
AC = √(81 + 144)
AC = √225
AC = 15 cm
AG = √(AC² + CG²)
AG = √(15² + 20²)
AG = √(225 + 400)
AG = √625
AG = 25 cm
Keliling segitiga ACG
= AC + CG + AG
= 15 + 20 + 25
= 35 + 25
= 60 cm (Opsi A) -
2. Jawaban Albertxi
Keliling ACG = AC+CG+AG
AC² = AB² + BC²
= 9² + 12²
= 225
AC = √225 = 15 cm
CG = AE = 20 cm
AG² = AC² + CG²
= 15² + 20²
= 625
AG = √625 = 25 cm
K = AC+CG+AG
= 15+20+25
= 60 cm (a)