Stasioner f(x)=sin(2x-π/3)

f(x) = sin (2x - π/3)
Titik stasioner diperoleh jika f'(x) = 0
f'(x) = 2 cos (2x - π/3) = 0
=> cos (2x - π/3) = 0
=> cos (2x - π/3) = cos π/2
=> 2x - π/3 = π/2 + k . 2π atau 2x - π/3 = -π/2 + k . 2π
=> 2x = 5π/6 + k . 2π ................ 2x = -π/6 + k . 2π
=> x = 5π/12 + k . π .................... x = -π/12 + k . π
=> x = 5π/12 ................................. x = -π/12 (TM) => untuk k = 0
=> x = 17π/12 ................................ x = 11π/12 => untuk k = 1
=> x = 29π/12 (TM) ..................... x = 23π/12 => untuk k = 2
Jadi x = {5π/12, 11π/12, 17π/12, 23π/12}

f(x) = sin (2x - π/3)
f(5π/12) = sin (2.5π/12 - π/3) = sin (5π/6 - 2π/6) = sin 3π/6 = sin π/2 = 1
f(11π/12) = sin (2.11π/12 - π/3) = sin (11π/6 - 2π/6) = sin 9π/6 = sin 3π/2 = -1
f(17π/12) = sin (2.17π/12 - π/3) = sin (17π/6 - 2π/6) = sin 15π/6 = sin 5π/2 = 1
f(23π/12) = sin (2.23π/12 - π/3) = Sin(23π/6 - 2π/6) = sin 7π/2 = -1
Jadi titik stasioner nya :
Titik satsioner maksimum = (5π/12, 1) dan (17π/12, 1)
Titik stasioner minimum = (11π/12, -1) dan (23π/12 , -1)

TM = tidak memenuhi