suatu fungsi f(x) =ax + b , jika f(2) = 3 dan f(5) = 15 ,maka f(10) =

F(5) = a.5 + b = 15
F(2) = a.2 + b = 3

(5-2)b = (15-3) a.2 + 4 =3
3b = 12 a. (4+2) = 3
b = 4 a = 6 : 3
a = 2


F(10) = ax + b
= 2.10 + 4
= 20 + 4
= 24

f(x) = ax + b
f(2) = 2a + b = 3
f(5) = 5a + b = 15
------------------------- --
....... -3a = -12 => a = 4

2a + b = 3 => b = 3 - 2a = 3 - 2(4) = -5

f(x) = ax + b = 4x - 5
f(10) = 4(10) - 5 = 35