panjang diagonal sisi alas pada balok jika panjang 4 cm dan lebar 3cm adalah? tolong di jawab nomor 8, 9, 10. makasih

8) p = 4 , l = 3
P.diagonal = akar 4^2 + 3^2
= akar 16+9
= akar 25
= 5

Nomor 8 :
p = 4 cm
l = 3 cm

Diagonal sisi alas
= √(4² + 3²)
= √(16 + 9)
= √25
= 5 cm (Opsi C)

Nomor 9 :
p = 5 cm
l = 3 cm
t = 4 cm

Diagonal sisi alas
= √(p² + l²)
= √(5² + 3²)
= √(25 + 9)
= √34

Diagonal ruang
= √((√34)² + 4²)
= √(34 + 16)
= √50
= √(25 x 2)
= 5√2 cm

Nomor 10 :
Diagonal sisi = 8√2
s √2 = 8√2
s = 8√2 / √2
s = 8 cm