kak, minta tolong nomor 2 ya,, yang f(2016) itu.,,

f(x) + 2x f(1/x) = 3(x + 1) ............ (1)

Jika x nya diganti dengan 1/x maka
f(1/x) + 2.1/x f(1/(1/x)) = 3(1/x + 1) ===> kali x
x f(1/x) + 2f(x) = 3x(1/x + 1)
2f(x) + x f(1/x) = 3(1 + x) ........... (2)
Eliminasi (1) dan (2)
f(x) + 2x f(1/x) = 3(x + 1) ===> kali 1
2f(x) + x f(1/x) = 3(1 + x) ===> kali 2

f(x) + 2x f(1/x) = 3(x + 1)
4f(x) + 2x f(1/x) = 6(x + 1)
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-3 f(x) = -3 (x + 1)
f(x) = x + 1
Jadi f(2016) = 2016 + 1 = 2017