jika f(x)=ax+6, f(x)=5, g(x)=x2+1 dan (gof)(2)=50. nilai a adalah

f(x) = ax + 6
g(x) = x²+1
(gof) (x) = (f(x)²+1
=(ax+6)²+1

subs nilai x=2
(gof) (2)=50
(2a+6)²+1=50
(2a+6)²=49
2a+6=√49
2a+6=7
2a=7-6
a=1/2
jadi nilai a =½