no14. jika rangkaian dipasang pada tegangan 24v.berapa daya masing2 lampu (R1,R2,R3,R4)

Rp = (1/R₁ + 1/R₂ + 1/R₃)⁻¹
      = [1 / (2 Ω) + 1 / (3 Ω) + 1 / (6 Ω)]⁻¹ = 1 Ω
Rs = Rp + R₄
      = 1 Ω + 1 Ω = 2 Ω
I = V / Rs
  = 24 V / (2 Ω) = 12 A

P₄ = I² R₄ = (12 A)²(1 Ω) = 144 W
P₃ = I₃² R₃ = (V / R₃)² R₃ = V² / R₃ = (24 V)² / (6 Ω) = 96 W
P₂ = V² / R₂ = (24 V)² / (3 Ω) = 192 W
P₁ = V² / R₁ = (24 V)² / (2 Ω) = 288 W