Matematika

Pertanyaan

lim x → 0 1-cos^2x/6x sin x

2 Jawaban

  • Bab Limit
    Matematika SMA Kelas X

    Lim ((1 - cos² x) / (6x . sin x)
    x→0

    = Lim ((sin² x)/(6x . sin x))
    ...x→0

    = 1/6
  • [tex]$\begin{align}\lim_{x\to0}\frac{1-\cos^2x}{6x\cdot\sin x}&=\lim_{x\to0}\frac{\sin^2x}{6x\cdot\sin x}\\&=\lim_{x\to0}\frac{\sin x}{6x}\\&=\boxed{\frac16}\end[/tex]

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