Matematika

Pertanyaan

Nilai dari 4 sin 210 derajat - cos 120 derajat + sin 330 derajat =

2 Jawaban

  • [tex]$\begin{align}&4\cdot\sin210^{\circ}-\cos120^{\circ}+\sin330^{\circ}\\\\&=4\cdot\sin(180^{\circ}+30^{\circ})-\cos(180^{\circ}-60^{\circ})+\sin(360^{\circ}-30^{\circ})\\&=4\cdot-\sin30^{\circ}-(-\cos60^{\circ})+(-\sin30^{\circ})\\&=4\cdot-\frac12-\left(-\frac12\right)+\left(-\frac12\right)\\&=-2+\frac12-\frac12\\&=\boxed{-2}\end[/tex]
  • 4.-1/2√2 - (-1/2) + (-1/2)
    = -4/2√2 + 1/2 - 1/2
    = -4/2√2
    = -2√2

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