Jika 2log3 = p dan 2log7 = q , maka 27log42 adalah...

[tex]^2\log{3}=p,^2\log{7}=q \\ ^3\log{2}=\frac{1}{p}, ^3\log{7}=\frac{q}{p} \\ \\ \\ ^{27}\log{42}=^{3^3}\log{(2\times 3\times 7)} \\ \frac{1}{3}^3\log{(2\times 3\times 7)} \\ \frac{1}{3}(^3\log{2}+^3\log{3}+^3\log{7}) \\ \frac{1}{3}(\frac{1}{p}+1+\frac{q}{p})=\frac{1}{3}\times \frac{p+q+1}{p} \\ \displaystyle \frac{p+q+1}{3p}[/tex]