Hitunglah PH 200 ml NH4OCN 0,03 m
Kimia
Ayuanandah
Pertanyaan
Hitunglah PH 200 ml NH4OCN 0,03 m
1 Jawaban
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1. Jawaban BLUEREAPER
NH3OH + HCN ---> NH4OCN
jika dianggap reaksi sempurna
[H+] = √(kw/kb [G] )
[H+] = √(kw/kb [0,03(1000)/200])
[H+] = √(10^-14/kb × 0,15)
pH = -log [H+]
pH = -log √(10^-14/kb × 0,15)
pH = 7 + log √kb - log 0,15
masukkan nilai kb jika diberi