Matematika

Pertanyaan

Tolong dibantu nomer 8,10 dan 11 nya
Tolong dibantu nomer 8,10 dan 11 nya

1 Jawaban

  • 11) a = 3i + 4j + 5k
    => |a| = √(3^2 + 4^2 + 5^2) = √(9 + 16 + 25) = √50 = 5√2
    b = -2i + 8j + 2k
    => |b| = √((-2)^2 + 8^2 + 2^2) = √(4 + 64 + 4) = √72 = 6√2
    Cos @ = a.b / |a|.|b|
    Cos @ = (3(-2) + 4(8) + 5(2)) / (5√2)(6√2)
    Cos @ = (-6 + 32 + 10) / 60
    Cos @ = 36/60 = 6/10 = 3/5 = sa/mi
    de = √(5^2 - 3^2) = √(25 - 9) = √16 = 4
    Sin @ = de/mi = 4/5
    Sin 2@ = 2 sin @ cos @ = 2 . 4/5 . 3/5 = 24/25

    10) ABCD jajar genjang maka AB = DC
    => b - a = c - d
    => d = a + c - b = (6,4,2) + (2,2,-2) - (-1,3,7) = (9,3,-7)
    @ = sudut antara AC dan BD
    AC = c - a = (2,2,-2) - (6,4,2) = (-4,-2-4)
    => |AC| = √((-4)^2 + (-2)^2 + (-4)^2) = √(16 + 4 + 16) = √36 = 6
    BD = d - b = (9,3,-7) - (-1,3,7) = (10, 0, -14)
    => |BD| = √(10^2 + 0^2 + (-14)^2) = √(100 + 0 + 196) = √296 = 2√74
    Cos @ = AC.BD / |AC|.|BD|
    = (-4(10) + (-2)(0) + (-4)(-14)) / 6 . 2√74
    = (-40 + 0 + 56) / 12√74
    = 4 / 12√74
    = 1 / 3√74