100 mL larutan ca(OH)2 0,1 m dicampurkan ke dalam larutan CH3COOH 0,1 M,ternyata PH campurannya =5. jika harga Ka asam asetat 1x10^5,maka volume larutan CH3COOH
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Pertanyaan
100 mL larutan ca(OH)2 0,1 m dicampurkan ke dalam larutan CH3COOH 0,1 M,ternyata PH campurannya =5. jika harga Ka asam asetat 1x10^5,maka volume larutan CH3COOH 0,1 adalah..
1 Jawaban
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1. Jawaban dithakkamjong
dik : pH = 5
[H+] = 10^-5
Ca(OH)2= 100ml × 0,1 M = 10 mmol
Ka = 10^-5
CH3COOH = 0,1 M
dit : Volume CH3COOH
jawab :
[H+] = Ka×Al/Bk
10^-5 = 10^-5×Al/10
10^-4= Al×10^-5
Al = 10^(-4-(-5)
Al = 10 mmol
n Al = v × M
10 mmol = v × 0,1
v = 100 ml