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Pertanyaan

jika larutan garam nax 0,01M mempunyai ph=9,harga ka asam hx sebesar

1 Jawaban

  • pH = pKw - pOH
    9 = 14 - pOH
    pOH = 5
    pOH = - log OH-
    5 = - log OH-
    OH- = 10^-5
    OH- = √ Kw / Ka x Mg
    10^-5 = √ 10^-14 / Ka x 0.01
    10^-10 = 10^-16 / Ka
    Ka = 10^-6

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