Nomer 5 cara nya plis

Hope it could help. Toodles!

[tex]3^{x} = a =\ \textgreater \ x = 3loga \\ 3^{y} = b =\ \textgreater \ y = 3logb \\ 3(3loga) + 4 (3logb) / 2(3loga) + 3(3logb) \\ 3loga^{3}b^{4} / 3loga^{2}b^{3} \\ a^{2}b^{3}loga^{3}b^{4} \\ a^{2}b^{3}loga^{2}b^{3} + a^{2}b^{3}logab \\ 1 + a^{2}b^{3}logab (E)[/tex]