persamaan garis melalui titik (-2,5) dan sejajar garis x-3y+2=0 gimana cara cepatnya tolong di bantu

x - 3y + 2 = 0
-3y = -x -2 (bagi -3)
y = 1/3x + 2/3
gradien = 1/3

y-y1 = m(x-x1)
y-5 = 1/3(x-(-2)
y-5 = 1/3(x+2)
y-5 = 1/3x + 2/3
y = 1/3x + 2/3 +5
y = 1/3x + 5 2/3