Kak tolong bantuin ya, please... butuh kali kak, tentang turunan fungsi pembagian.

f(x) = 2√x / x = 2x^1/2 / x = 2x^(1/2 - 1) = 2x^-1/2
f'(x) = 2.-1/2 x^(-1/2 - 1)
f'(x) = - x^-3/2 = -1/(x^3/2) = -1/(x√x)

Pakai Rumus
u = 2√x = 2x^1/2 => u' = x^-1/2
v = x => v' = 1
f'(x) = (u' v - v' u)/v^2
= (x^-1/2 . x - 1 . 2x^1/2) / x^2
= (x^1/2 - 2x^1/2)/x^2
= (√x - 2√x)/x^2
= -√x / x^2 (jawabannya bisa sampai sini saja)
atau kita uraikan lagi
= - (x^1/2)/x^2
= - x^(1/2 - 2)
= - x^(-3/2)
= -1/(x^3/2)
= -1/(x√x)