simpangan baku dari data:3,4,4,5,6,6,7 adalah.....

x bar = 3+4+4+5+6+6+7/7 = 35/7 = 5
Simpangan baku (S)
S = √sigma (x - x bar)²/n
= √(3-5)²+(4-5)²+(4-5)²+(5-5)²+(6-5)²+(6-5)²+(7-5)²/7
= √4+1+1+0+1+1+4/7
= √12/7
*maaf kalau salah