Jika f(x)=3x-2 , x e R dan f o g(x)= 6x+! maka rumus fungsi g (x) adalah....

(f o g) (x) = f (g(x))
(f o g) (x) = f (x² + 2x – 3)
(f o g) (x) = 2 (x² + 2x – 3) – 3
(f o g) (x) = (2x² + 4x – 6) – 3
(f o g) (x) = 2x² + 4x – 9
(f o g) (2) = 2 (2)² + 4 (2) – 9
(f o g) (2) = 8 + 8 – 9
(f o g) (2) = 7

good luck...